this post was submitted on 01 Nov 2024
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Programming
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Seems excessive to convert everything to rust when you can use std::shared_ptr and std::weak_ptr to eliminate the memory safety issue?
I have never seen a single C++ codebase do that. It helps but it's not a practical full solution.
Using smart pointers doesn’t eliminate the memory safety issue, it merely addresses one aspect of it. Even with smart pointers, nothing is preventing you from passing references and using them after they’re freed.
To be fair, it's entirely possible to make the same and very similar mistakes in Rust, too.
Yes
Definitively not.
I'm fairly sure use after free isn't possible unless you explicitly use unsafe code right?
It's compiler enforced is the point.
I wonder how many issues rewriting everything in another language will create?
Just as many issues as not reading the article.
I get what you're saying, but I think the issue with optional memory safety features is that it's hard to be sure you're using it in all the places and hard to maintain that when someone can add a new allocation in the future, etc. It's certainly doable, and maybe some static analysis tools out there can prove it's all okay.
Whereas with Rust, it's built from the ground up to prove exactly that, plus other things like no memory being shared between threads by accident etc. Rust makes it difficult and obvious to do the wrong thing, rather than that being the default.
From the original document:
My interpretation is that smart pointers are allowed, as long it’s systematically enforced. Switching to a memory safe language is just one example.