this post was submitted on 01 Dec 2023
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

Solution Threads

M T W T F S S
1 2 3
4 5 6 7 8 9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25

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Icon base by Lorc under CC BY 3.0 with modifications to add a gradient

console.log('Hello World')

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Welcome everyone to the 2023 advent of code! Thank you all for stopping by and participating in it in programming.dev whether youre new to the event or doing it again.

This is an unofficial community for the event as no official spot exists on lemmy but ill be running it as best I can with Sigmatics modding as well. Ill be running a solution megathread every day where you can share solutions with other participants to compare your answers and to see the things other people come up with


Day 1: Trebuchet?!


Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ or pastebin (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

FAQ


🔒This post will be unlocked when there is a decent amount of submissions on the leaderboard to avoid cheating for top spots

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[–] [email protected] 1 points 11 months ago (1 children)

I think I found a decently short solution for part 2 in python:

DIGITS = {
    'one': '1',
    'two': '2',
    'three': '3',
    'four': '4',
    'five': '5',
    'six': '6',
    'seven': '7',
    'eight': '8',
    'nine': '9',
}


def find_digit(word: str) -> str:
    for digit, value in DIGITS.items():
        if word.startswith(digit):
            return value
        if word.startswith(value):
            return value
    return ''


total = 0
for line in puzzle.split('\n'):
    digits = [
        digit for i in range(len(line))
        if (digit := find_digit(line[i:]))
    ]
    total += int(digits[0] + digits[-1])


print(total)
[–] [email protected] 3 points 11 months ago (1 children)

Looks very elegant! I'm having trouble understanding how this finds digit "words" from the end of the line though, as they should be spelled backwards IIRC? I.e. eno, owt, eerht

[–] [email protected] 2 points 11 months ago* (last edited 11 months ago)

It simply finds all possible digits and then locates the last one through the reverse indexing. It’s not efficient because there’s no shortcircuiting, but there’s no need to search the strings backwards, which is nice. Python’s startswith method is also hiding a lot of that other implementations have done explicitly.