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I think, while the death star could probably take out a borg cube, as mentioned by others with the size discrepancy alone, I think it becomes a potentially harder calculus if you field even two, potentially more, borg cubes. At that point, it sort of falls down to how the borg shields hold up against blasters and ion cannons, and that seems like kind of a shitfuck. There's not a real answer to it, because both of them are either totally fictional or theoretical technologies. That maybe also holds true for things like the death star's laser, but as others have said, there's better analogues for that which we see the borg go up against and lose.
I think there's also potentially an interesting difference here in how the Borg's warp drive works vs Star wars hyperdrives. Could the Borg cube just jump right up to the death star and then board immediately? Could they bypass the laser by just warping in? I dunno, also a consideration, also unanswerable.
Would the death star be hackable? I dunno, the star wars computers might be too different, or even just too fucking old. They seem more fucked up than the star trek computers, anyways.
I dunno. They probably both get wiped by the halo ring, in any case.
But the cubes are pretty maneuverable. So yeah, the DS has the superlaser and a whole host of little guns, the odds of it being able to bring the superlaser to bear on the Cube are pretty small. Now, if you count all the fighters and bombers on the DS I’m pretty sure the Cube is toast. Overwhelming numbers of fighter lasers, bombers, and Death Star defense cannons.