this post was submitted on 07 Oct 2024
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Science Memes

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273
Behold, a square (sopuli.xyz)
submitted 4 weeks ago by [email protected] to c/[email protected]
30 comments fedilink hide all child comments
 

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[–] [email protected] 155 points 4 weeks ago (5 children)

As long as we ignore the parallel sides requirement, sure.

[–] [email protected] 89 points 4 weeks ago (2 children)

And that the 90 degree angles should be interior angles.

[–] [email protected] 43 points 4 weeks ago (2 children)

And that polygons should only consist of straight lines.

[–] [email protected] 35 points 4 weeks ago

Yes sure, in Euclidean geometry, but this is clearly keyhole shaped geometry.

[–] [email protected] 1 points 3 weeks ago

geodesics

[–] [email protected] 12 points 4 weeks ago (1 children)

They're also not actually right angles, as the curvature starts departing from the angles origin. They may be approximately 90, down to many many small decimal places, but they are not 90.

[–] [email protected] 26 points 4 weeks ago* (last edited 4 weeks ago)

That's not accurate. If you are measuring the angle of a line intersecting with a curved surface, you measure against the tangent at the point of contact/intersection. It can be and still is exactly 90 degrees.

[–] [email protected] 32 points 4 weeks ago (2 children)

Take shitposts seriously and point out their obvious errors

-Carl Friedrich Gauss, probably

[–] [email protected] 20 points 4 weeks ago (2 children)

Science memes is not r/shitposting? I would assume the person is serious when posting here.

[–] [email protected] 4 points 4 weeks ago

gasp!!! it is c/!!!

[–] [email protected] -4 points 4 weeks ago

I would assume the person is serious when posting here.

This sounds like a "you" problem

[–] [email protected] 3 points 4 weeks ago

The name of that Gauss?

Ampere

[–] [email protected] 18 points 4 weeks ago

c/gatekeeping squares

[–] [email protected] 10 points 4 weeks ago

You're no fun

[–] [email protected] 5 points 4 weeks ago

Polar coordinate square?

[–] [email protected] 30 points 4 weeks ago (1 children)

I remember enough from geometry to know this is horseshit and be annoyed at it but not enough to actually prove why

[–] [email protected] 11 points 4 weeks ago (1 children)

Sides must be straight and parallel two and two.

[–] [email protected] 3 points 4 weeks ago

QED

[–] [email protected] 11 points 4 weeks ago (3 children)

What are the 4 sides?

[–] [email protected] 16 points 4 weeks ago

The black lines

[–] [email protected] 7 points 4 weeks ago (1 children)

The semi-circle is one side, then the 2 straight edges, and the arc between them is the 4th side.

[–] [email protected] 6 points 4 weeks ago (1 children)

That's what I thought. The only way on which this has four sides is if the semi -circle is a side. But if that's the case, then I don't know wha the definition of "side" is

[–] [email protected] 9 points 4 weeks ago (1 children)

Knock knock. Do you have a moment to discuss non-euclidean geometry?

[–] [email protected] 10 points 4 weeks ago

/slams door

[–] [email protected] 5 points 4 weeks ago (1 children)

Someone may want to double-check my math on this one, but the length of the sides will be dependant on the radius of the smaller circle

ϴ=π+1-√(π^2+1), l=(2π-ϴ)r_1, l is the length of the sides. r_1 is the radius of the smaller circle

[–] [email protected] 4 points 4 weeks ago* (last edited 4 weeks ago) (1 children)

I look at your diagram and see:

ϴ= L/(L+R)

And

2π-ϴ = L/R

I solved those (using substitution, then the quadratic formula) and got

L= π-1 ± √(1+π²) ~= 5.44 or -1.16

Whether or not a negative length is meaningful in this context is an exercise left to the reader

Giving (for L=5.44):

ϴ~= 0.845 ~~48.4°

I'm surprised that it solved to a single number, maybe I made a mistake.

[–] [email protected] 3 points 4 weeks ago

That lines up pretty similarly with what I found also. The angle should be a constant since there is only one angle where the relationship would be true. I just left it in terms of π because I try to avoid rounding.

Having said that, L would be a ratio of r; which I think lines up with what you found as well.

[–] [email protected] 9 points 4 weeks ago (2 children)

it’s homeomorphic to a square, so why not

[–] [email protected] 3 points 4 weeks ago

See, you get it

[–] [email protected] 2 points 2 weeks ago

I'll tell you why not! You hippie homeopaths are all the same! Science has scienced the evidence that there's no evidence for homopathic medicines otter than the libido effect.